Answer:
To determine the volume, we can use the formula:
mass of solute (g) / molar mass (g/mol) x 1 / molarity (mol/L) = volume (L)
First, we need to calculate the molar mass of LiNO3:
LiNO3 = Li + N + 3O
= 6.94 g/mol + 14.01 g/mol + 3(16.00 g/mol)
= 68.94 g/mol
Now, we can plug in the values:
5.66 g / 68.94 g/mol x 1 / 0.57 mol/L = 0.174 L
Finally, we convert liters to milliliters:
0.174 L x 1000 mL/L = 174 mL
Therefore, 174 mL of 0.57 M LiNO3 solution has 5.66 g of solute.