Question

Markovnikov addition of HCl to propene involves:

A. initial attack by a chlorine ion. B. initial attack by a chlorine atom. C. isomerization of 1-chloropropane. D. formation of a propyl cation. E. formation of an isopropyl cation.

Answer 1

Answer choice (A)

Step-by-step explanation:

Markovnikov addition of HCl to propene involves the initial attack by a chlorine ion (A) on the carbon-carbon double bond of propene. The chlorine ion carries a negative charge and is attracted to the positively charged carbon atom of the double bond. The attack results in the formation of a carbocation intermediate, which is stabilized by the chloride ion. The chloride ion then adds to the carbocation, resulting in the formation of 2-chloropropane. The addition follows Markovnikov's rule, which states that the hydrogen atom of HCl adds to the carbon atom of the double bond that already has more hydrogen atoms attached to it.