To determine the molecular formula of compound A, we will follow these steps:
1. Identify the molecular ion (M) peak: m/z 85 (since "m: ss" is likely a typo and should be "m: 85")
2. Identify the presence of nitrogen: M+1 peak at m/z 86 with 6% abundance relative to M, suggests the presence of one nitrogen atom (N).
3. Calculate the number of carbon atoms: M+2 peak at m/z 87 with 10% abundance relative to M, suggests the presence of 10/1.1 ≈ 9 carbon atoms (C).
Now, we can determine the molecular formula of compound A:
C9HxN, where x is the number of hydrogen atoms.
To find the number of hydrogen atoms, we will use the molecular ion mass:
85 = 9(12.01) + x(1.01) + 14.01
85 = 108.09 + x(1.01)
x ≈ 13
So, the molecular formula of compound A is C9H13N.
Now, let's consider the IR absorption information:
- Absorption at 1620-1680 cm-1 indicates a C=C double bond (alkene) or C=N bond.
- No absorption at 3010-3090 cm-1 suggests the absence of an alkene with sp2 hybridized C-H.
Possible structure(s) for compound A can be drawn by considering a C=C double bond or a C=N bond with the given molecular formula C9H13N. One possible structure is N-ethyl-3-methyl-2-butene:
CH3-CH2-CH=CH-CH(CH3)-NH-CH2-CH3
Remember that other structures may also fit the description, but this is one example.