Question

5. The position of a particle moving along x axis is given by X=12t² -2t³ where x is in meter and t is second, determine [a] the position of the particle at t=2s [b] the velocity and acceleration of the particle at t=3s.​

Answer 1

Step-by-step explanation:

a) The position of the particle at t=2sec

X=12t² -2t³ = 12*2² -2*2³=48-16=32m

b)velocity of particle = dx/dt=24t-6t²

velocity of particle at t=3sec is 24*3-6*3² =72-54=18 m/s

Acceleration = dv/dt = 24-12t

acceleration at t=3sec is 24-12(3)= -12 m/s²