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A rigid container holds a gas at a pressure of 0.29 atm at a temperature of -94 °C. What will the pressure be when the temperature is increased to 177 °C?

User Kierie
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1 Answer

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To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas.

The combined gas law is expressed as:

(P1V1)/T1 = (P2V2)/T2

where P1 and T1 are the initial pressure and temperature, respectively, and P2 and T2 are the final pressure and temperature, respectively. V1 and V2 represent the volume of the gas, which is assumed to be constant in this problem.

We can rearrange the equation to solve for P2:

P2 = (P1 x T2) / T1

Plugging in the given values:

P1 = 0.29 atm

T1 = -94 °C = 179 K (converted to Kelvin by adding 273.15)

T2 = 177 °C = 450 K

V1 = V2 (assumed to be constant)

P2 = (0.29 atm x 450 K) / 179 K

P2 = 0.72 atm (rounded to two significant figures)

Therefore, the pressure will be approximately 0.72 atm when the temperature is increased to 177 °C.

User Aphexlog
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