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A gas sample occupies a volume of 2.5 L at a temperature of 195 K and a pressure of 0.832 atm. How many moles of gas are there?

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Answer:

We can use the ideal gas law to solve for the number of moles of gas:

PV = nRT

where P is the pressure in atm, V is the volume in liters, n is the number of moles, R is the ideal gas constant (0.0821 L atm/mol K), and T is the temperature in Kelvin.

We are given P = 0.832 atm, V = 2.5 L, and T = 195 K. Substituting these values into the equation, we get:

(0.832 atm)(2.5 L) = n(0.0821 L atm/mol K)(195 K)

Simplifying, we get:

2.08 = 16.0775n

Dividing both sides by 16.0775, we get:

n = 0.129 mol

Therefore, there are approximately 0.129 moles of gas in the sample.

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