Answer:
Explanation:
Letting x=0, we see that the assertion is incorrect. It is always fun (if you don’t have a life) to try to salvage questions making as few changes as possible. I suggest that
\text {If }\tan A=\dfrac{x}{x-1} \text { and \}tan B=\dfrac{1}{2x-1}, \text { then }A-B=45^o.
Of course, it should be 45 increased by sum multiple of 180^o. But in case it gives you ides for other such questions,
tan(A−B)=tanA−tanB1+tanAtanB
=xx−1−12x−11+xx−112x−1
=2x2−x−x+12x2−3x+1+x
=2x2−2x+12x2−2x+1
=1
And you finish if it is of interest.