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Find the center and radius of the circle represented by the equation below. x2+y2-18x+10y+25=0. (You have to convert it to standard to find the center and radius).

Find the center and radius of the circle represented by the equation below. x2+y2-18x-example-1

2 Answers

5 votes

Answer: Center: (9,-5), Radius = 9

User Jakir Hosen Khan
by
7.8k points
2 votes

Answer:

centre = (9, - 5 ) and radius = 9

Explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

given

x² + y² - 18x + 10y + 25 = 0

subtract 25 from both sides and collect x / y terms together

x² - 18x + y² + 10y = - 25

using the method of completing the square

add ( add half the coefficient of the x/ y terms )² to both sides

x² + 2(- 9)x + 81 + y² + 2(5)y + 25 = - 25 + 81 + 25

(x - 9)² + (y + 5)² = 81 = 9²

then

centre = (9, - 5 ) and radius = 9

User Gabriel Rohden
by
8.7k points