Question

A student has been given two blocks. One block has one of the following letters, A, B, C, D, E, and F, on each side. The other block has one of the following numbers, 1, 2, 3, 4, 5, 6, 7, 8, on each side. If the student rolls both blocks, what is the probability of rolling the letter C and an even number?

Answer 1

1/12 which is 8.33%

Explanation:

The first block has a total of 6 choices, so getting C would be a 1/6 chance.

The second block has a total of 8 choices, the even numbers make up half of the choices, so it would be a 4/8, or simplify to be a 1/2 chance.

Multiply the fractions together to get 1/12.

You can convert this to a percentage by just doing the division of 1 / 12 = 0.0833333333, which as a percentage is 8.33%