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X²+8x+10=(x+p²)+q find the value of p and q

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We can start by expanding the right side of the equation and then compare the coefficients of x and the constant term on both sides to determine the values of p and q.

Expanding the right side, we get:

x + p² + q

Now we can compare the coefficients of x on both sides:

On the left side, the coefficient of x is 8.

On the right side, the coefficient of x is 1.

So we have:

1 = 8

This is not possible, so there must be an error in the equation.

Perhaps you meant to write the equation as:

x² + 8x + 10 = (x + p)² + q

In this case, we can expand the right side and compare coefficients again:

(x + p)² = x² + 2px + p²

So:

(x + p)² + q = x² + 2px + p² + q

Comparing coefficients of x on both sides, we get:

8 = 2p

Therefore, p = 4.

Now we can compare the constant terms on both sides:

10 = p² + q

Substituting the value we found for p, we get:

10 = 16 + q

Therefore, q = -6.

So the values of p and q are:

p = 4
q = -6
User Paulo Amaral
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