In the given figure, find the distance of a point A from origin.Explain why?

Question

asked Sep 10, 2024 35.5k views

2 Answers

Abhinav Aggarwal · Answer 1 · 2024-09-11T10:37:05+0000

Formula to find the distance between two points is given by -

$\small \underline{ \boxed{ \sf{ \pmb{ Distance = √( (y_2 -y_1)^2 + (x_2-x_1)^2)}}}}\\$

As per question, points are -

On substituting the values :-

$\: \: \: \: \: \longrightarrow \sf {Distance(XQ) = √( (0-4)^2 + (0-3)^2 )}\\$

$\: \: \: \: \:\longrightarrow \sf {Distance (XQ)= √( (-4)^2 + (-3)^2 )}\\$

$\: \: \: \: \:\longrightarrow \sf {Distance(XQ) = √( 16+9)}\\$

$\: \: \: \: \:\longrightarrow \sf {Distance (XQ)= √( 25) }\\$

$\: \: \: \: \:\longrightarrow \sf {Distance(XQ) = 5}\\$

$\: \: \: \: \:\longrightarrow \boxed{ \tt{ \pmb{ \red{Distance(XQ) = 5 }}}}\\$

$\\ \therefore \underline{ \cal{ \pmb{The \:distance \: of \: the\: two \:points \: is \: \frak{\purple{ 5.} }}}}\\$

Ashark · Answer 2 · 2024-09-16T23:52:56+0000

Answer:

distance = 5 units

Explanation:

we can calculate the distance d using the distance formula

d =
$\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2 }$

with (x₁, y₁ ) = (0, 0 ) and (x₂, y₂ ) = (3, 4 )

d =
√((3-0)^2+(4-0)^2)

=
√(3^2+4^2)

=
√(9+16)

=
√(25)

= 5