Question

In the given figure, find the distance of a point A from origin.Explain why? ​

Answer 1

Formula to find the distance between two points is given by -

`\small \underline{ \boxed{ \sf{ \pmb{ Distance = √( (y_2 -y_1)^2 + (x_2-x_1)^2)}}}}\\`

As per question, points are -

• X (3,4)

• Q(0,0)

On substituting the values :-

`\: \: \: \: \: \longrightarrow \sf {Distance(XQ) = √( (0-4)^2 + (0-3)^2 )}\\`

`\: \: \: \: \:\longrightarrow \sf {Distance (XQ)= √( (-4)^2 + (-3)^2 )}\\`

`\: \: \: \: \:\longrightarrow \sf {Distance(XQ) = √( 16+9)}\\`

`\: \: \: \: \:\longrightarrow \sf {Distance (XQ)= √( 25) }\\`

`\: \: \: \: \:\longrightarrow \sf {Distance(XQ) = 5}\\`

`\: \: \: \: \:\longrightarrow \boxed{ \tt{ \pmb{ \red{Distance(XQ) = 5 }}}}\\`

`\\ \therefore \underline{ \cal{ \pmb{The \:distance \: of \: the\: two \:points \: is \: \frak{\purple{ 5.} }}}}\\`

Answer 2

distance = 5 units

Explanation:

we can calculate the distance d using the distance formula

d =
`\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2 }`

with (x₁, y₁ ) = (0, 0 ) and (x₂, y₂ ) = (3, 4 )

d =
`√((3-0)^2+(4-0)^2)`

=
`√(3^2+4^2)`

=
`√(9+16)`

=
`√(25)`

= 5