Question

Write the slope-intercept form of the equation of the line that is parallel to AB and passes through Point X. Show all

work for full credit.
A
(-10, 8)
-10 -8
X
(-5, 10)
ch
4
N
10
10
2 B
&
Y
(2, 3)
-10
2
5
8
10

Answer 1

To find the slope of line AB, we can use the slope formula:

slope of AB = (y2-y1)/(x2-x1) = (3-8)/(2-(-10)) = -5/12

Since we want to find the equation of a line parallel to AB and passing through point X(-5,10), we know that the slope of this new line will also be -5/12.

Now we can use the point-slope form of the equation of a line to find the equation of the line:

y - y1 = m(x - x1), where m is the slope of the line and (x1,y1) is a point on the line.

So, plugging in the values we know:

y - 10 = (-5/12)(x - (-5))

Simplifying:

y - 10 = (-5/12)x - (25/12)

y = (-5/12)x + (145/12)

This is the slope-intercept form of the equation of the line parallel to AB and passing through point X.