Question

Chlorine gas reacts with aqueous sodium bromide to produce aqueous sodium chloride and bromine gas. What is the balanced net ionic equation for this reaction?

Cl2(g) + 2 Br1-(aq) → 2 Cl1-(aq) + Br2(g)


Cl2(g) + 2 Na1+(aq) + 2 Br1-(aq) → 2 Na1+(aq) + 2 Cl1-(aq) + Br2(g)


2 Cl1-(g) + 2 Na1+(aq) + 2 Br1-(aq) → 2 Na1+(aq) + 2 Cl1-(aq) + 2 Br1-(g)


Cl2(g) + 2 NaBr(aq) → 2 NaCl(aq) + Br2(g)

Answer 1

Step-by-step explanation:

Whole formula equation:

Cl₂(g) + 2NaBr(aq) → 2NaCl(aq) + Br₂(g)

We can expand this to get the full ionic equation:

Cl₂(g) + 2Na⁺(aq) + 2Br⁻(aq) → 2Na⁺(aq) + 2Cl⁻(aq) + Br₂(g)

Cancelling out spectator ions (ions that don't change) on both sides:

Cl₂(g) + 2Na⁺(aq) + 2Br⁻(aq) → 2Na⁺(aq) + 2Cl⁻(aq) + Br₂(g)

And our final result, is the net ionic equation:

Cl₂(g) + 2Br⁻(aq) → 2Cl⁻(aq) + Br₂(g)