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What is the moment of inertia of the solid sphere for rotation about an axis through the edge of the sphere? When the mass is 2.8kg and the diameter is 30cm

User Loonatick
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The moment of inertia of a solid sphere for rotation about an axis through the edge of the sphere can be calculated using the formula:

I = (2/5) * m * r^2

where I is the moment of inertia, m is the mass of the sphere, and r is the radius of the sphere.

In this case, the mass of the sphere is 2.8 kg and the diameter is 30 cm. We first need to find the radius, which is half the diameter:

r = d/2 = 30 cm / 2 = 15 cm = 0.15 m

Substituting the values into the formula, we get:

I = (2/5) * m * r^2

I = (2/5) * 2.8 kg * (0.15 m)^2

I = 0.063 kg*m^2

Therefore, the moment of inertia of the solid sphere for rotation about an axis through the edge of the sphere is 0.063 kg*m^2.