Question

2cos(2x+4)= square root of 3

Answer 1

1)x=13

2)x=Undefined

3)x=20

Explanation:

1) 2cos(2x+4)=√3

(2cos(2x+4))/2=√3/2

cos(2x+4)=√3/2

2x+4=cos^-1(√3/2)

2x+4=30

2x=30-4

2x=26

2x/2=26/2

x=13

2)tan2x=0

2x=tan^-1(0)

2x=0

2x/2=0/2

x=undefined

3)Sin^2(3x)=3/4

(sin3x)^2=3/4

√(sin3x)^2=√(3/4)

sin3x=√3/2

3x=sin^-1(√3/2)

3x=60

3x/3=60/3

x=20

Answer 2

1)x=13

2)x=Undefined

3)x=20

Explanation:

1) 2cos(2x+4)=√3

(2cos(2x+4))/2=√3/2

cos(2x+4)=√3/2

2x+4=cos^-1(√3/2)

2x+4=30

2x=30-4

2x=26

2x/2=26/2

x=13

2)tan2x=0

2x=tan^-1(0)

2x=0

2x/2=0/2

x=undefined

3)Sin^2(3x)=3/4

(sin3x)^2=3/4

√(sin3x)^2=√(3/4)

sin3x=√3/2

3x=sin^-1(√3/2)

3x=60

3x/3=60/3

x=20