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If x is inversely proportional to y and x = 40 when

y = 5, find
(i) the value of x when y = 25,
(ii) an equation connecting x and y,
(iii) the value of y when x = 400.​

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Given : x is inversely proportional to y and x = 40 when y = 5

To Find : (i) the value of x when y = 25,

(ii) an equation connecting x and y,

(iii) the value of y when x = 400.​

Solution:

x is inversely proportional to y


\implies x \ \infty \ 1/y


\implies x = k/y


\implies xy = k

x = 40 when y = 5


\implies 40(5) = k


\implies 200 = k


\implies xy = 200


y = 25


\implies x(25) = 200


\implies \bold{x = 8}

equation connecting x and y


\bold{xy = 200}


x = 400.


\implies 400(y) = 200


\implies \bold{y = 0.5}

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