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Determine the magnitude of the partial charges in HBr given that the bond length is 1.41 angstroms

and the dipole moment is 0.82 debye.

User Choman
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1 Answer

3 votes

Answer:

The magnitude of the partial charges in HBr is approximately 1.95 × 10^-19 C.

Step-by-step explanation:

The magnitude of the partial charges in a polar covalent bond can be determined using the formula:

μ = q × d

where μ is the dipole moment, q is the magnitude of the partial charges, and d is the bond length.

In this case, the dipole moment of HBr is given as 0.82 debye, which is equivalent to 0.82 × 3.336 × 10^-30 Cm (since 1 debye = 3.336 × 10^-30 Cm). The bond length is given as 1.41 angstroms, which is equivalent to 1.41 × 10^-10 meters.

Plugging these values into the formula, we get:

0.82 × 3.336 × 10^-30 Cm = q × 1.41 × 10^-10 meters

Solving for q, we get:

q = (0.82 × 3.336 × 10^-30 Cm) / (1.41 × 10^-10 meters) ≈ 1.95 × 10^-19 C

Therefore, the magnitude of the partial charges in HBr is approximately 1.95 × 10^-19 C.

User KC Baltz
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