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Given the system if equations

6x + 2y = -6
3x - 4y = -18

1. (0, -3)
2. (-1, 0)
3. (-2, 3)
4. (-14, -6)

Given the system if equations 6x + 2y = -6 3x - 4y = -18 1. (0, -3) 2. (-1, 0) 3. (-2, 3) 4. (-14, -6)-example-1
User Somatik
by
7.7k points

2 Answers

5 votes

Answer:

Explanation:

Elimination-

Let's solve your system by elimination.

6

+

2

=

63

;

4

=

18

Multiply the second equation by -6, then add the equations together.

(6�+2�=−63)

(

4

=

18

)

Becomes:

6

+

2

=

63

6

+

24

=

108

Add these equations to eliminate x:

26

=

45

Then solve

26

=

45

for y:

26

=

45

26

26

=

45

26

(Divide both sides by 26)

=

45

26

User Chadit
by
8.3k points
3 votes

Answer:


(- 2, 3 )

Explanation:


6x + 2y = - 6 → (1)


3x - 4y = - 18 → (2)

multiplying (1) by 2 and adding to (2) will eliminate y


12x + 4y = - 12 → (3)

add (2) and (3( term by term to eliminate y


15x + 0 = - 30


15x = - 30 ( divide both sides by 15 )


x = - 2

substitute
x = - 2 into either of the 2 equations and solve for y

substituting into (1)


6(- 2) + 2y = - 6


- 12 + 2y = - 6 ( add 12 to both sides )


2y = 6 ( divide both sides by 2 )


y = 3

solution is
\bold{(- 2, 3 )}

User Tyler Davis
by
8.5k points

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