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A dog is walking nicely at a velocity of 1.23m/s[E] when it sees a dead squirrel. If it travels a displacement of 34.3m[E] in a time of 7.3s, what is its acceleration?

User Fonseca
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1 Answer

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To find the acceleration of the dog, we need to use the following formula:

a = (v_f - v_i) / t

Where:

a = acceleration

v_f = final velocity

v_i = initial velocity

t = time

In this case, the initial velocity (v_i) of the dog is 1.23 m/s to the east (positive direction) and the final velocity (v_f) is unknown. The displacement (d) of the dog is 34.3 m to the east (positive direction) and the time (t) taken to travel this distance is 7.3 s.

We can use the formula for displacement to find the final velocity:

d = (v_f + v_i) / 2 * t

Rearranging this formula to solve for v_f, we get:

v_f = (2 * d / t) - v_i

Substituting the given values, we get:

v_f = (2 * 34.3 m / 7.3 s) - 1.23 m/s

v_f = 4.04 m/s

Now we can substitute the values of v_f, v_i, and t into the formula for acceleration:

a = (v_f - v_i) / t

a = (4.04 m/s - 1.23 m/s) / 7.3 s

a = 0.410 m/s^2 [E]

Therefore, the acceleration of the dog is 0.410 m/s^2 to the east (positive direction).

User Ankon
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