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What must be the mass of a chunck of aluminum that takes 8550 J of engery ti be heated from 50 C to 72 C

User Grambot
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The amount of energy required to heat a substance is directly proportional to its mass and the temperature change. The specific heat capacity of aluminum is 0.903 J/g°C, which means that it takes 0.903 Joules of energy to heat 1 gram of aluminum by 1 degree Celsius.

To calculate the mass of aluminum required to absorb 8550 J of energy to be heated from 50°C to 72°C, we can use the following equation:

Q = mcΔT

where Q is the amount of energy absorbed, m is the mass of the substance, c is the specific heat capacity, and ΔT is the temperature change.

Rearranging the equation to solve for mass, we get:

m = Q / (c * ΔT)

Substituting the given values, we get:

m = 8550 J / (0.903 J/g°C * (72°C - 50°C))

m = 8550 J / (0.903 J/g°C * 22°C)

m = 435.29 grams

Therefore, the mass of aluminum required to absorb 8550 J of energy to be heated from 50°C to 72°C is approximately 435.29 grams.
User Sohilv
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