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Physics

Consider a
man of mass sokg
standing lom from a woman with
a mass of skg. The attractive
grauitional force between them
would be?

User Jdoroy
by
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1 Answer

4 votes
The attractive gravitational force between the man and the woman can be calculated using the formula for the gravitational force:

F = G * (m1 * m2) / r^2

where F is the gravitational force, G is the gravitational constant (6.6743 × 10^-11 N·m^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between their centers of mass.

Substituting the given values, we get:

F = (6.6743 × 10^-11 N·m^2/kg^2) * [(50 kg) * (60 kg)] / (1 m)^2

F = 2.00329 × 10^-7 N

Therefore, the attractive gravitational force between the man and the woman is approximately 2.00329 × 10^-7 N.
User Nobilik
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8.0k points