bh, where b is the base and h is the height of the parallelogram.
In the case of the circle, the base of the parallelogram is the circumference of the circle, which is equal to 2πr, where r is the radius of the circle. The height of the parallelogram is the distance from the center of the circle to the edge of the circle, which is also the radius r. Therefore, we have:
b = 2πr
h = r
Substituting these values into the formula for the area of a parallelogram, we get:
Area = bh = (2πr)(r) = 2πr^2
So the formula for the area of a circle is derived from the formula for the area of a parallelogram by using the circumference of the circle as the base and the radius of the circle as the height.