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g a 0.750 kg hammer is moving horizontally at 9.50 m/s when it strikes a nail and comes to rest after driving it 1.00 cm into a board. (a) calculate the duration of the impact in seconds. .02105 incorrect: your answer is incorrect. s (b) what was the average force in newtons exerted on the nail?

User Greenif
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1 Answer

6 votes

Answer:

(a) t = 0.02111

(b) F = 337.5 N

Step-by-step explanation:

We can apply work energy theorem to solve this problem,


0 - (1)/(2)mv^2 = F_(avg).\Delta x

(change in kinetic energy = Force applied)

substituting the values given in the question,


- (0.75)/(2)3^2 = F_(avg).0.01

solving we get,


F_(avg) = -337.5 \, N

We have the equation,


F_(avg) = ma_(avg)

substituting the value of m and F we get,


a_(avg) = -450 \, m/s^2

We can calculate the duration of impact using the kinematical equations,


v = u + at


0 = 9.5 - 450t


t = 0.02111 s

User Krishna Raj Salim
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