Question

Assume that a procedure yields a binomial distribution with a trial repeated

n=16 times.
k=13 successes given the probability
q= 0.23 of success on a single trial.

(Report answer accurate to 4 decimal places.)

Answer 1

Using the binomial distribution formula, we can find the probability of getting k=13 successes in n=16 trials with a probability of success q=0.23 on a single trial:P(X=13) = (16 choose 13) * (0.23)^13 * (1-0.23)^3P(X=13) = 0.0082Therefore, the probability of getting 13 successful trials out of 16 repeated trials with a probability of success of 0.23 on a single trial is 0.0082, accurate to 4 decimal places.