Question

the gas law for an ideal gas at absolute temperature (in kelvins), pressure (in atmospheres), and volume is , where is the number of moles of the gas and is the gas constant. suppose that, at a certain instant, atm and is increasing at a rate of .10 atm/min and l and is decreasing at a rate of .15 l/min. find the rate of change of with respect to time at that instant if moles. round your answer to the nearest thousandth.

Answer 1

dT/dt=2.680K/M

Step-by-step explanation:

In this case we have:

P=8atm

R=0.0821

dP/dt=0.10 atm/min

V=10L

dV/dt=0.15L

n=10 moles

given that PV=nRT

d(PV)/dt=d(nRT)/dt

P(dV/dt)+V(dP/dt)=nRdT/dT

8*0.15+10*0.10=10*0.0821* dT/dt

dT/dt=2.6796589525

dT/dt=2.680K/m

(If it was not right please let me know)