Question

if a steel container with a constant volume has 50.0 atm air at 30.0 c and it's temperature rises to 70.0 what's it's pressure

Answer 1

P V = N R T ideal gas equation

P1 = T1 V. N. R remain constant

P2 = T2

P2 / P1 = T2 / T1 dividing equations

P2 = P1 (T2 / T1) = 50 * 343 / 303 (0 deg C = 273 deg K)

P2 = 56.6 atm