Answer:
The probability that the second child will have the disease depends on whether the parents have one or two copies of the recessive disease-causing allele. Since both parents are heterozygous carriers, they each have one copy of the disease-causing allele and one normal allele.
When they have a child, each parent randomly passes one allele to their offspring. There are four possible allele combinations that can result in the child inheriting the disease:
The child inherits the disease-causing allele from both parents (homozygous recessive)
The child inherits one disease-causing allele from one parent and one normal allele from the other parent (heterozygous carrier)
The child inherits the normal allele from both parents (homozygous dominant)
The probability of each of these combinations depends on the probabilities of the parents passing on each of their alleles. Since the parents are each heterozygous carriers, there is a 25% chance that they will both pass on the disease-causing allele, a 50% chance that they will each pass on one disease-causing allele, and a 25% chance that they will both pass on the normal allele.
Therefore, the probability that the second child will have the disease is 25%.