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Two parallel lines touch the circle at points A and B respectively. If the area of the circle is 25 pie cm square then find AB

User Weigan
by
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1 Answer

3 votes

Answer:

the distance between the two tangent points is 10 cm.

Explanation:

Since the two parallel lines are tangent to the circle, they must be equidistant from the center of the circle.

Let O be the center of the circle, and let AB be the distance between the two tangent points. Then, we have:

AB = 2 * OA

Also, we know that the area of the circle is given by:

A = πr^2

where r is the radius of the circle. Since we are given that the area of the circle is 25π cm^2, we have:

25π = πr^2

Simplifying this equation, we get:

r^2 = 25

Taking the square root of both sides, we get:

r = 5

Now, we can use the fact that the two tangent lines are equidistant from the center of the circle to find AB. Let's draw a diagram:

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B

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-----O-----

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A

Since OA is the radius of the circle, we have OA = 5 cm. Therefore:

AB = 2 * OA

= 2 * 5

= 10

So, the distance between the two tangent points is 10 cm.

User Hojjat
by
8.4k points