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Suppose the pot is then filled with 2 liters of water ( a mass of 2,000 grams ). How much heat has to be absorbed by the water to get it up to the same temperature?

Q= m * c * △t = ______ *______ *______ = ______ joules

User Chinloyal
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Q = 2,000 * 4.18 * 80= 668,800 Joules

The equation you mentioned is the formula for calculating the amount of heat required to change the temperature of a substance. Let's break it down:

Q represents the amount of heat energy needed, measured in Joules.

m represents the mass of the substance, measured in grams.

c represents the specific heat capacity of the substance, which is a measure of how much heat energy is needed to raise the temperature of 1 gram of the substance by 1 degree Celsius. Specific heat is measured in Joules per gram per degree Celsius.

Δt represents the change in temperature, measured in degrees Celsius.

So, in this case, we have:

m = 2,000 grams (the mass of the water)

c = 4.18 J/g°C (the specific heat of water)

Δt = 80°C (the change in temperature needed to bring the water up to boiling)

Plugging these values into the formula, we get:

Q = m * c * Δt

Q = 2,000 * 4.18 * 80

Q = 668,800 Joules

Therefore, to bring 2 liters of water up to boiling point, we need to absorb 668,800 Joules of heat energy.

User ProdigySim
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