Explanation:
Since line d has a constant y-value of -2, any point equidistant from F and d must lie on a horizontal line passing through the point (0, 1) (which is the midpoint of the line segment connecting F to the y-axis).
Therefore, we can eliminate the points (-3, 5) and (-5, 3) since they do not lie on a horizontal line passing through (0, 1).
To determine which of the remaining two points, (0, 1) and (3, 0), is equidistant from F, we can calculate their distances from F:
Distance from (0, 1) to F: sqrt[(0-0)^2 + (1-3)^2] = sqrt[4] = 2
Distance from (3, 0) to F: sqrt[(3-0)^2 + (0-3)^2] = sqrt[18] = 3sqrt[2]
Since neither distance is equal, we can conclude that there is no point on the graph that is equidistant from F and d. Therefore, the answer is none of the given options.