Question

From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1cm are removed. (as shown in the adjoining figure). Find the area of the remaining sheet. (show working too)

Answer 1

The area of remaining sheet is 536 cm²

Since, we know that the area of circle
`=\pi * r^2`

Area of bigger circle
`=(22)/(7) *14*14`

`=44*14`

`=616 \ \text{cm}^2`

Thus, the area of bigger circle is 616 cm²

Similar way, the area of 2 smaller circles
`=2\pi r^2`

`=2*(22)/(7) *3.5*3.5`

`=44*0.5*0.5`

`=77 \ \text{cm}^2`

Thus, the area of 2 smaller circle is 77 cm²

`\text{Area of rectangle}=\text{Length}*\text{Breadth}`

`=3*1=3 \ \text{cm}^2`

Thus, the area of rectangle is 3 cm²

Now, remaining area of sheet = Area of bigger circle − Area of both smaller circle − Area of rectangle

`=616-77-3=536 \ \text{cm}^2`

Hence, area of remaining sheet is 536 cm²