Question

If you put a leash on a 12kg cat and try to take it for a walk, it will not be happy. Eventually it will refuse to walk and you will have to drag it home. If you are dragging the cat with a horizontal force of 55 N and the coefficient of friction between the cat and the grass is 0.3. What is the Acceleration of the cat

Answer 1

Answer:
`1.64 m/s^(2)` (3 sig figs)

`1.6 m/s^(2)` (2 sig figs)

Explanation:

First we need to find the weight of the cat using F=ma (117.72 = 12 * 9.81)

Using 117.72 we can find the force of friction by doing F = μ * N (35.316 = 0.3 * 117.72)

After we find the friction force we simply subtract the friction force from the applied force (19.684 = 55 - 35.316)

Using 19.684 we can find the acceleration using F / m = a (19.684 / 12 = 1.64)

From there you reduce your answer to the number of sig figs, which I think is 2 unless otherwise specified.