Question

If x = 1, y = -2, z = 3 find the value of x3 + y3 + z3
– 3xy

Answer 1

x = 1

y = -2

z = 3

Then the given equation =

1³+ -2³ + 3³ - 3( 1 × (-2) × 3)

=> 1 - 8 + 27 -3(-6)

=> 20+18

=> 38

Explanation:

Answer 2

x = 1

y = -2

z = 3

Then the given equation =

1³+ -2³ + 3³ - 3( 1 × (-2) × 3)

=> 1 - 8 + 27 -3(-6)

=> 20+18

=> 38