Question

A thief is running away from a scene and reaches a speed of 10 m/s in 5 seconds what is the thief acceleration

A. 2 m/s^2
B. 8 m/s^2
C. 18 m/s^2
D. 1 m/s^2

Answer 1

Answer:
`2 m/s^(2)` (Assuming the thief starts from 0 m/s)

Step-by-step explanation:

First you take the final velocity (10) and subtract the initial velocity (0)

`10-0=10`

Then you divide the difference by the time to get the acceleration

`10/5=2`

This all uses the equation

`V_(f)-V_(i)=ta`