Question

What is the Molarity of a 0.5 Liter solution that contains 3.84 moles of NaCI?
SHOW WORK ​

Answer 1

The molarity of a 0.5 L solution that contains 3.84 moles of NaCl is 7.68 M.

Here’s the work: Molarity (M) = moles of solute / liters of solution Substituting the given values into the equation: Molarity (M) = 3.84 moles / 0.5 L = 7.68 M.