Answer:
- I₁ ≈ 0.1036∠68.75°
- I₂ ≈ 0.1637∠50.31°
Explanation:
You want the solution in polar form of the system of equations ...
- (2+j6)I₁ -j4·I₂ = 0
- j·I₁ +(8-j10)I₂ = 2
The usual solution methods for a system of equations apply. The attached calculator shows the currents to be ...
- I₁ ≈ 0.1036∠68.75°
- I₂ ≈ 0.1637∠50.31°
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Additional comment
For systems of equations in which the coefficients don't lend themselves to elimination or substitution methods, we prefer matrix methods to find a solution. A suitable calculator makes this relatively easy.