Question

Find a quadratic function of the form y = ax that passes through the point (-2,16).
Y=

Answer 1

y = 4x^2

Explanation:

To find a quadratic function of the form y = ax^2 that passes through the point (-2,16), we need to substitute the coordinates of the point into the equation and solve for the coefficient a.

Substituting x=-2 and y=16 into the equation, we get:

16 = a(-2)^2

16 = 4a

a = 4

Therefore, the quadratic function of the form y = ax^2 that passes through the point (-2,16) is:

y = 4x^2