Question

Helena drops a ball from 25 feet above a lake. The formula t= 1/4√25-h describes the time t in seconds that the ball is h feet above the water. How many feet above the water will the ball be after 1 second? ​

Answer 1

We can use the formula t= 1/4√25-h to find the height h of the ball above the water after 1 second.

t=1 second, so we substitute t=1 into the formula:

1 = 1/4√25-h

Multiplying both sides by 4√25-h, we get:

4√25-h = 1

Squaring both sides, we get:

16(25-h) = 1

Expanding the left side, we get:

400 - 16h = 1

Subtracting 400 from both sides, we get:

-16h = -399

Dividing both sides by -16, we get:

h = 24.9375

Therefore, the ball will be about 24.94 feet above the water after 1 second.