Question

In the figure, BC=26, EF=22. Find OD. Round to the nearest hundredth.

Answer 1

Check the picture below.

`\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ c^2=a^2+o^2 \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{13}\\ a=\stackrel{adjacent}{OD}\\ o=\stackrel{opposite}{11} \end{cases} \\\\\\ (13)^2= (OD)^2 + (11)^2\implies 13^2-11^2=OD^2\implies 48=OD^2 \\\\\\ √(48)=OD\implies 6.93\approx OD`