Question

Given a 2.5-hr unit hydrograph with a peak discharge of 100 m3/s, what would be the peak discharge for a 2.5-hr storm with 2.5 cm of runoff?

Answer 1

To solve this problem, we can use the following formula:

Peak discharge = (Rainfall depth) x (Unit hydrograph peak discharge)

First, we need to convert the rainfall depth from centimeters to meters:

2.5 cm = 0.025 m

Next, we can use the given unit hydrograph peak discharge of 100 m3/s and substitute it into the formula along with the rainfall depth of 0.025 m:

Peak discharge = (0.025 m) x (100 m3/s)

Peak discharge = 2.5 m3/s

Therefore, the peak discharge for a 2.5-hr storm with 2.5 cm of runoff would be 2.5 m3/s.