149k views
5 votes
Need helpppppp
12 points!!

Need helpppppp 12 points!!-example-1
User Ravishi
by
8.1k points

2 Answers

0 votes

There is a total of 50 chickens and cows.

Chickens have 2 legs each. Cows have 4 legs each.

There are 118 legs in total. We are focusing on how much chickens there are.

CHICKENS=50-COWS.

2CHICKENS+4COWS=118

2(50-COWS)+4COWS=118

100-2COWS+4COWS=118

2COWS=118-100

2COWS=18

C0WS=18/2

COWS=9

CHICKENS+9=50

CHICKENS=50-9

CHICKENS=41

PROOF:

2*41+4*9=118

82+36=118

118=118

This is a bit long and confusing but I hope this helps!

User Venimus
by
7.6k points
3 votes

Answer:

41 chickens and 9 cows

Explanation:

Chickens have 2 legs each.

Cows have 4 legs each.

There are 50 animals total.

There are 118 legs total.

You can set up a system to represent this situation.

Let x represent the number of chickens and y represent the number of cows.

x + y = 50

2x + 4y = 118

Multiply the first equation by 2 and subract it from the second equation.

2x + 4y = 118

- 2x + 2y = 100

_____________

2y = 18

y = 9

So there are 9 cows. There are 50 animals total so there must be 41 chickens.

User Josh Hamet
by
8.4k points

No related questions found