Question

Two buses leave a station at the same time and travel in opposite directions. One bus travels 18 miles hour faster than the other. If the two buses are 768 miles apart after 6 hours, what is the rate of each bus?

Answer 1

Answer: one is 55 and the other is 73

Explanation:

lets say x is for the slower bus. for every hour the become x+x+18

and this is happening for 6 hours so its is 6(2x+18)=768

x=55

x+18=73

Answer 2

Answer: the slower bus travels at 55 miles per hour and the faster bus travels at 73 miles per hour.

Explanation:

distance = rate x time

768 = 6x + 6(x + 18)

Simplifying this equation, we can distribute the 6 on the right-hand side:

768 = 6x + 6x + 108

Combining like terms, we get:

768 = 12x + 108

Subtracting 108 from both sides:

660 = 12x

Dividing both sides by 12:

x = 55

So the slower bus is traveling at 55 miles per hour. To find the speed of the faster bus, we can add 18:

x + 18 = 55 + 18 = 73