Question

Can someone please help me?​

Answer 1

The person above me gave the correct answer :)

Answer 2

2) x = 3√5; y = 6;

3) x = 12√2; y = 12;

4) x = 45∘; y = 45∘;

5) x = 60∘; y = 30∘

Explanation:

2) Use trigonometry:

`\cos(60∘) = (3)/(y)`

Use the property of the proportion to find y:

`y = (3)/( \cos(60∘) ) = (3)/(1) / (1)/(2) = (3)/(1) * (2)/(1) = 6`

Use the Pythagorean theorem to find x:

`{x}^(2) = {y}^(2) + {3}^(2) = {6}^(2) + {3}^(2) = 36 + 9 = 45`

`x > 0`

`x = √(45) = 3 √(5)`

3) Use trigonometry:

`\sin(45∘) = (12)/(x)`

Use the property of the proportion to find x:

`x = (12)/( \sin(45∘) ) = (12)/(1) / ( √(2) )/(2) = (12)/(1) * (2)/( √(2) ) = 12 √(2)`

Use trigonometry:

`\tan(45∘) = (12)/(y)`

Use the property of the proportion to find y:

`y = (12)/( \tan(45∘) ) = (12)/(1) = 12`

4) Use trigonometry:

`\tan(x∘) = (3)/(3) = 1`

x = 45∘

`\tan(y∘) = (3)/(3) = 1`

y = 45∘

5) Use trigonometry:

`\cos(x∘) = (4)/(8) = (1)/(2) = 0.5`

x = 60∘

`x = \sin(y∘) = (4)/(8) = (1)/(2) = 0.5`

y = 30∘