Answer:
For number 2: 8/165
Explanation:
The total number of coins = 11 ( 3 + 4 + 4 = 11).
The probability of picking a nickel first = 3/11 ( 4 nickels out of 11 total).
The probability of picking a dime second = 4/10 = 2/5 ( 3 dimes out of 10 coins left).
The probability of picking the third coin as a quarter = 4/9 ( 3 quarters out of 9 coins left).
I don't know the other problem, sorry.