Question

What is the molarity of a solution in which 40.1 g of calcium chloride is dissolved in enough water to prepare 429 mL of solution?​

Answer 1

To calculate the molarity of the solution, we first need to find the number of moles of calcium chloride in the solution.

The molar mass of calcium chloride (CaCl2) is 40.08 g/mol (1 calcium atom + 2 chlorine atoms).

The number of moles of calcium chloride can be calculated as:

moles of CaCl2 = mass of CaCl2 / molar mass of CaCl2

moles of CaCl2 = 40.1 g / 40.08 g/mol

moles of CaCl2 = 1.00 mol

Now that we know the number of moles of calcium chloride in the solution, we can calculate the molarity using the following formula:

molarity = moles of solute / volume of solution (in liters)

First, we need to convert the volume of solution from milliliters to liters:

429 mL = 0.429 L

Now we can calculate the molarity:

molarity = 1.00 mol / 0.429 L

molarity = 2.33 M

Therefore, the molarity of the solution is 2.33 M.