Answer:
1 and 19
Explanation:
3(x-10)^2 = 3(x^2-20x+100) = 3x^2 - 60x + 300
If 3x^2 - 60x + 300 = 243, 3x^2 - 60x + 57 = 0
Divide by 3 to get x^2 - 20x + 19 = 0
use the quadratic equation (-b±√(b²-4ac))/(2a) to get
(20±√324)/2 = (20±18)/2 = 1 and 19
9.3m questions
12.1m answers