Question

Three whole numbers have a total of 50

The first number is a multiple of 15
The second number is nine times the third number.
Work out the three numbers.

Answer 1

The first number is 30 ( a multiple of 15)
50-30= 20(the total of the other two numbers)
2x9=18
18+2=20
So the second number is 18 and the third number is 2.
The three numbers are 30, 18, 2

Answer 2

Let a be the first, b be second and c be the third whole number.

Since the sum of these three numbers is 100.

So,
`a+b+c=100` (equation 1)

Since, The first number is a multiple of 15

Therefore,
`a = 15n`

And, the second number is ten times the third number.

`b = 10c`

Substituting the values of 'a' and 'b' in equation 1

So,
`15n+10c+c=100`

`15n+11c=100`

`11c=100-15n`

`c=(100-15n)/(11)`

Therefore,
`100-15n` should be exactly divisible by 11.

So, by taking
`n= 1` and 2,
`100-15n` is not divisible by 11

Let
`n =3`

`c=(100-15*3)/(11)`

`c= 5`

Now, second number (b)
`= 10c = 10*5=50`

As,
`a+b+c=100`

`a+50+5=100`

`a+55=100`

`a=45`

Therefore, the three whole numbers are 45, 50, 5.