Question

An object is weight with spring balance in air and then totally with water, the reading on the balance are 0.98N and 0.88N repectively. Calculate the desity of the object.

Answer 1

Weight of object = .98 N

Buoyant force equals weight of water displaced = .10 N

Weight of object - weight of water displaced = .98 - .10 = .88 N

Density = Weight of object / Weight of equivalent weight of water

ρ = .98 / .10 = 9.8 specific gravity of object

Since the density of water = 1 g / cm^3

the density of the object is 9.8 g / cm^3 (9800 kg/m^3)