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A dwelling with a general lighting load of 10,000 VA requires a minimum of how

many 15 A branch circuits?
A. 8
B. 3
C. 10
D. 6

1 Answer

2 votes

Step-by-step explanation:

The calculation is as follows:

The general lighting load is 10,000 VA.

The voltage used in homes is typically 120 volts.

Dividing the general lighting load by the voltage gives us the amperage: 10,000 VA / 120 volts = 83.33 amps

According to the National Electrical Code (NEC), a 15-amp branch circuit can handle a maximum of 15 amps.

To determine the number of 15-amp branch circuits required, we divide the amperage by the maximum allowed on one circuit: 83.33 amps / 15 amps = 5.55

Therefore, we need at least 6, 15-amp branch circuits to handle the general lighting load of 10,000 VA.

The answer is (D) 6.

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