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Find the work done by a force F = 4i − 3j + 2k that moves an object from the point (3, 2, -1) to the point (2, -1, 4) along a straight line. The distance is measured in meters and the force in newtons.

User Nknj
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1 Answer

3 votes

Answer:

15 N

Step-by-step explanation:

work done by the force in vector form is given by the equation,


W = \vec{F}.\delta \vec{r}

where . represents the dot product.

in the given question,


F = 4i - 3j + 2k

and


\delta \vec{r} = (2 - 3)i + (-1 - 2)j + (4 - (-1))k


\delta \vec{r} = -i - 3j + 5k

on doing the dot product we get


W = -4 + 9 + 10\\W = 15

Hopefully this answer helped you.

User DanKodi
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